Murder of Crows - 2 Rules Questions

First, the rules say a player cannot have two Wild Crows showing in his/her Murder at the same time. However, it is possible to end up with two Wild Crows showing through no fault of the owning player. Consider the following chain of events. The player plays a Wild Crow as another card (a D for example). On a later turn, the player covers the Wild Crow with a matching letter card (the D, in this case). The player then plays a Wild Crow to a different stack (say an R). Now, his opponent plays an M and takes the D, uncovering the buried Wild Crow and leaving two exposed at the same time. How is this situation to be resolved?

Second, what is the precise sequence of events with regard to preventing the effect of an M card in a multi-player game when an M. There are two possible ways to play. (A) All other players decide whether to block with a card containing the same number of crows (or a Wild Crow). After they have decided whether or not to block, the active player may take a card from any one player that didn't block. (B) The active player first identifies which player (and card) is being targeted, then that player -- and that player only -- decides whether to block. Which is correct?

BTW, we are really enjoying this game. It's light, fast, and still surprisingly strategic!

Hello Edralla,

Glad you are enjoying the game.

M: choose the card you want to Misplace, if that player blocks the effect that's it the effect is cancelled.

Wild Crow: when you play a WIld Crow only 1 Wild Crow may be showing in your Murder at a time. This does not prevent more than 1 Wild Crow from showing in your Murder due to card effects.

For example if you have no Wild Crows, you may play a Wild Crow in any slot. If you have a Wild Crow, then you could only play another Wild Crow in that same slot (to fulfill the only 1 showing rule). If in the very rare case you have 2 or more Wild Crows already showing you would not be able to play a Wild Crow at all.

Hope this helps,